Find the roots of the following quadratic equ | vedclass

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Question

(A) Given the quadratic equation: $x^{2}+2x-2=0$Step $1$: Move the constant term to the right side: $x^{2}+2x=2$Step $2$: Add the square of half the c

Vedclass · Accepted Answer

$-1+\sqrt{3}, -1-\sqrt{3}$

Vedclass · Answer

(A) Given the quadratic equation: $x^{2}+2x-2=0$Step $1$: Move the constant term to the right side: $x^{2}+2x=2$Step $2$: Add the square of half the coefficient of $x$ to both sides. The coefficient of $x$ is $2$,so half of it is $1$,and its square is $1^{2}=1$. Adding $1$ to both sides:$x^{2}+2x+1=2+1$Step $3$: Write the left side as a perfect square: $(x+1)^{2}=3$Step $4$: Take the square root of both sides: $x+1 = \pm\sqrt{3}$Step $5$: Solve for $x$: $x = -1 \pm \sqrt{3}$Thus,the roots are $-1+\sqrt{3}$ and $-1-\sqrt{3}$.

Find the roots of the following quadratic equation by the method of completing the square: $x^{2}+2x-2=0$

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